Wednesday, December 2, 2015

Basic Electrical Engineering Dharmsinh Desai University 2009 Question paper

Are you searching Dharmsinh Desai University question papers? Here you can find Basic Electrical Engineering Question paper of 2009 in DDU.

Tutorial -1
B.E. Sem: 1 (ALL)
SUBJECT NAME : Basic Electrical Engineering

Q-1 Fill in the blanks:

1.Reluctance in magnetic circuit is equivalent to ______ in electical circuit.
2.Unit of magnetic flux density is _______. (wb, wb/m, wb/sq.m)
3.Permeability of free space is ________.
4.Mmf per unit length is called ________.
5.Flux which does not follow desired path in a magnetic field is known as _____.
6.If area of cross section of a solenoid is a then S = _______.
7.1 Wb = _______ magnetic lines.

Q-2 Answer the following questions:

1.Why relative permeability of air is 1?
2.Define magnetic leakage.
3.What is leakage co-efficient?
4.Explain the effect of fringing effect.
5.State the KCL and KVL of magnetic circuit with equestion.

Q-3 Solve the examples:

1.An iron ring 15 cm in diameter, and 10 sq. cm in c.s. Is wound with 200 turns of wire. For a flux
density of 1 wb/sq. m, and a permiabilityof 500, find the exciting current.
2.An iron ring made of three parts has l1 = 10 cm, A1= 5 sq.cm. i2=8cm, A2 = 3 sq.cm, l3 = 6cm
and A3 = 2.5.sq.cm. It is wound with a ciol of 250 turns. Calculate the requuired to produce a
flux of 0.4 mwb in the ring. M1 = 2670, M2 = 1050, M3 = 650.
3.An iron ring 100 cm mean diameter, and 10 sq cm cross section has 1000 turns of copper wire
wound on it. If the permiability of the materialis 1500, and it is required to produce a flux density
of 1 Wb/sq.m.in an air gap of 2 mm width in the ring, find(1)reluctance of ring; (2)flux required,
(3) mmf required (4) current produced. Neglect leakage and fringing.
4.(a) iron ring wound with 500 turns solenoid produces a flux density 0.94 tesla in the ring carrying
a current pf 2.4 amps. The mean length of iron path is 80 cm, and that of an air gap is 1mm.
Determine relative permiabilityof iron.(b) Determine the coefficient of self inductaance, and
energy stored in the above arraangement, if the area of cross-section is 20 sq cm.
5.An eletromagnet of form shwon below is excited by two coils, each having 500 turns. When the
exciting current is 0.8 A, and the resulatant flux density gives permiabilityof 1250, calculate (1)
tltal reluctance (2) flux produced 0.5 cm airgap.
6.A magnetic coe made up of an alloy has the dimensions as shown in fig. Calculate the exciting
current required to produce a flux of 1 mWb in the airgap. Neglect leakage, and fringing. B/H
curve is as follows.

B(Tesla) 1 1.2 1.42 1.5125 1.6
H(AT/m) 200 400 1791.4 3300 6000
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